>>937533976Literally this.
If I missed the gold one, the second time that I pick, then my odds of 100% of getting a gold drop by the sampling space ratio of which there is, 2 probabilities remaining. as I have already selected a box with a gold ball in it.. there are only two possible probable outcomes that fit the solution of my chances of getting a golden ball.
Either I get a gold ball, or I don't.
I pick 1x more gold balls = 100% of that box containing gold balls.
If I pick 1xgold 1xgrey than 50% of the box has the possible chance of a gold ball.
Because the question is asking us, to ascertain with a certainty, of how many possible outcomes of selecting the second ball from your random box is going to be gold, therefore the probability of getting a gold ball is either 100% (both balls are gold in the box) or 50% where 1 ball is grey. We can rule out the third box, by default, as one golden ball has already been retrieved. So in summation there are only 2 possibilities out of 100%.
100%/2=50%