>>16693929 (OP)OK OP, let's say we have a right angle triangle, with two sides both 1 cm. We know that 1^2 + 1^2 = C^2, or that 1 + 1 = C^2.
Since both sides are equal, and all triangles have internal angles totalling 180 degrees, both of the non-right angles must be 45 degrees.
To find C, we'll use trigonometry. We know that the sine of 45 must equal either of the 1 cm sides over C cm, or 1/C. The sine of 45 is known to be 1/[2^(1/2)], thus 1/[2^(1/2)] = 1/C. If we multiply both sides by C, we find that C/[2^(1/2)] = 1. Multiplying both sides by [2^(1/2)] this time, we now get C = 2^(1/2). Since 1 + 1 = C^2, and C = 2^(1/2), we know that 1 + 1 = [2^(1/2)]^2 or 1 + 1 = 2.