Any thoughts on how I may be able to get the math community to assemble that sum, and how I can ensure I will be paid when doing the exchange?

The un found problem has certainly caused a lot more than a billion in damages and will continue to do so, beyond that, my proof includes things that significantly advance mathematics, more important than the addition of complex numbers, so it is absolutely worth the billion, a lot more considering by how much wealth it will create.

However having mathematicians assemble this sum is another problem, they are all famously poorfags with no power or influence, so that’s where this board comes in for suggestions.

>>16697245 (OP)
>not a single post on the board in the last 19 minutes
Welp

>>16697245 (OP)
Very cool anon, my associates will be with you shortly.

>>16697245 (OP)
I think I an probably find someone to give you about treefiddy for it

>>16697245 (OP)
if anon could do it, then the math community will figure it out for less than that

>>16697245 (OP)
I'm down to go knock on some doors if you need someone to come collect with you.
Also, where did you find it? I found an old shoe under a bridge the other day.
>However having mathematicians assemble this sum is another problem, they are all famously poorfags
Wut?
I happen to have it on good authority they can walk into any building they want and get $300k/yr starting.

>>16697375
A billion
300k/y/person
3333 years
6666 years with tax
13333 years with life expanses in murica (weak currency)
So you would need 1000 mathematicians saving up their salaries for a decade to assemble a billion

And that’s not total poorfag territory to you? As a reminder earth has a per-year GDP of around 100 thousand billions

>>16697245 (OP)
https://mathprize.net/posts/collatz-conjecture/
Best you can get is 120 million japanese yen. That comes out to 832722 USD. You can either:
1. Prove the conjencture, and get your prize plus eternal fame.
2. Keep spamming 4chan like a no life loser.

I wonder which choice OP will take.

>>16697245 (OP)
True mathematicians aren't driven by money or even notoriety, but to simply communicate their ideas.

>>16697419
also not being loved by parents

>>16697245 (OP)
1. No you don't have a proof of Collatz.
2. It has not caused more than a billion in damages, that's retarded.
3. Nobody cares to spend time on your wrong and retarded proof looking for the mistake.
4. Nobody cares.

>>16697245 (OP)
contact Nassim Taleb
he may help

>>16697245 (OP)
write a zero-knowledge proof(actual think g, look it up) of your claim & some money will be willing to arrive towards you

>>16697245 (OP)
Find a zero knowledge proof of collatz and auction it off in secret to industry. That's what I did when I found a poly time algorithm for 3SAT.

>>16697245 (OP)
so OP's fakematician guts are growling, understood

>>16697245 (OP)
Figure it out yourself smartass

terence tao already proved that the collatz conjecture

>>16697245 (OP)
>get the math community to assemble that sum, and how I can ensure I will be paid when doing the exchange?

probably a troll thread but still, so fucking good

I tried playing with the conjecture by juggling things in base-2 but kept hitting dead ends.

I wondered whether generalising the conjecture helps, turning the question from 3n+1 to m*n+1 where m > 1. Can m also effect what the divisor is when it's even, what if the mod (%) method changes between being even-odd (mod 2) to other numbers (mod m-1).

>>16700143
i prefer going in reverse, thinking of the system as branching series of odd numbers multiplied by powers of 2.
because of the way you get new branches (take one of the even parts of the previous sets, subtract one, divide by 3), the process can't create loops at all:

because [math]\frac{n-1}{3}[/math] is the only way to "go backwards," a loop would need either an even number from dividing an odd number by another odd number (impossible; excludes all even numbers as loop targets) or for one odd number [math]m[/math] to have multiple numbers [math]p[/math] such that [math]m=\frac{p-1}{3}[/math] (also impossible).

the 1-4 loop is a special case because 1 is the only solution to [math]3x+1=2^{2}x[/math] - it's the only place where the two operations overlap. in all other cases, [math]2^{2}x>3x+1[/math] (which, in ALL cases using naturals, including for 1, also applies for all powers of 2 of 3 or greater), and in ALL cases using naturals, including for 1, [math]3x+1>2x[/math]. in short, [math]2^2[/math] is the only way to get a loop, and the only loop it gets you is the 1-4 loop.

since by definition this construction hits everything that goes into the 1-4 loop, if you can prove it hits all of [math]\mathbb{N}[/math], you prove both parts of the conjecture simultaneously.