Assume there is a square in a graph. The verticies of this square are located at (0,0), (0,1), (1,0), (1,1). Now, we draw a line y=x to split the square in half. Below the line is colored in red. Above it is colored in blue. Now we draw a line y=2x. Above the line is colored in red. Now we draw a line y=4x. Above the line is colored in blue. Continue alternating this by generating lines of y=x*2^n where n is a nonnegative integer. What is the area of the square that's covered in blue?
Bonus. Let's repeat this but we also allow n to be a nonnegative integer. This means that when you draw slope y=x/2 we color everything below the slope blue, and when we draw y=x/4 we color everything below the slope red. What's the total area the blue portion of the square?

Why is the pic so shitty lmao

>>16711083 (OP)
I asked wolfman alpha, the answer is pi and then the log of some shit

>>16711340
The total area of the square is 1 square unit, so how can the area of part of the square be greater than 3? Just based on the picture it's like about 1/2

>>16711829
Wait I just realized the picture doesn't correlated to the exact question. The entire region below y=x is red and that's half, then the top half will keep alternating between red and blue, the biggest portions will be blue so it's more blue than red in the top half, so the answer is definitely between 1/2 and 1/4. Probably it's exactly 1/3 or 1/π since they like meme answers for these.