Search Results
8/7/2025, 9:09:13 AM
>>103211363
I can even eyeball the formula they're using for this gaussian
>f(t) = 13500 * e^(-((t - 1.87)^2)/(2 * 0.5^2))
13500 would be the expected peak
1.87 the amount of time (in decimal hours) since the start of the botting
With some adjustments and more eyeballing it would be possible to predict his CCV for the whole duration of the stream
I can even eyeball the formula they're using for this gaussian
>f(t) = 13500 * e^(-((t - 1.87)^2)/(2 * 0.5^2))
13500 would be the expected peak
1.87 the amount of time (in decimal hours) since the start of the botting
With some adjustments and more eyeballing it would be possible to predict his CCV for the whole duration of the stream
Page 1