The majority of /g/ are miserable fags and trannies that just write fizz buzz over and over.

>>105618175 (OP)
>unusable lingo to anyone above fridge IQ
>major traumatic nocoder cope

>>105618175 (OP)
>>105618424
fizz

>>105618602
>buzz

>>105618737
retardo

>>105618602
4

>>105618175 (OP)
I bet you can't write branchless fizzbuzz

>>105618789
>another nocoder zoomer joins the ranks of street shitters

>>105618811
>another projectionist projecting
>>105618789
buzz

>>105618808
Sit down kid,

>>105619108
You can't do it with Python. The loop will use a branching jump and also the code that prints numbers will use branching jumps. You need to use C:
int putchar(int);
static void prn(const char* s) {
void* labels[] = {&&loop, &&end};
loop:
putchar(*s);
goto *labels[*s++ == 0];
end:;
}
int main() {
const char* const digits = "\0""0123456789";
const char* const fizz = "\0""fizz";
const char* const buzz = "\0""buzz";
void* labels[] = {&&loop, &&end};
int i = 1;
loop:
const int d3 = i % 3 == 0;
const int d5 = i % 5 == 0;
putchar(digits[(1 + i / 10) * !(d3 | d5 | (i < 10))]);
putchar(digits[(1 + i % 10) * !(d3 | d5)]);
prn(fizz + d3);
prn(buzz + d5);
putchar('\n');
goto *labels[++i > 100];
end:;
}

>>105619419
Honestly this is OPs point exactly.

>>105618175 (OP)
Saar, are you prostitute?

>>105619448
Fizzbuzz is where all advances in computing are made though.

That, and hello world.

7F 45 4C 46 B2 0C B9 40 00 04 00 B3 01 EB 05 90 02 00 03 00 B0 04 EB 08 04 00 04 00 2C 00 00 00 CD 80 B3 4C B0 01 CD 80 34 00 20 00 01 00 00 00 00 00 00 00 00 00 04 00 45 45 45 45 4C 00 00 00 48 65 6C 6C 6F 20 57 6F 72 6C 64 0A

>>105620928
Yes.
https://codegolf.stackexchange.com/questions/215216/high-throughput-fizz-buzz/236630#236630