Thread 16835161

Ladies and Gentleman. I present to you my proof Cantor's second diagonal argument is false.

Q. E. D.

S=0.9999...
10S=9.999...
10S-S=9
9S=9
S=1

>>16835161 (OP)
Your list in step 1 is incomplete.

>>16835161 (OP)
Avoiding this problem is like 70% of the proof of the argument

>>16835161 (OP)
0.100....
Here's a number that's not in your list.
B. T. F. O.

>>16835161 (OP)
i don’t get it. you only showed me a finite list of 1s.

>>16835192
s = 0.9 remainder 0.1
10s = 9 remainder 1
10s-s = 8.1 remainder 0.9
9s = 8.1 remainder 0.9
s = 9 remainder 0.1
s != 1

>>16835455
What? Am I too stupid to understand? What's the point of the remainder?

>>16835192
>>16835455
Both of these are true, no? What's the joke

>>16835161 (OP)
go back to retarddit

If 0.999... = 1
what does 0.888... equal?

>>16838210
0? Subtract 1 from both sides

>>16835192
you cant computationally multiply infinite numbers therefore
10S=10*0.9999...

>>16838210
8/9.

>>16838248
You can whe you write them as a infinite sum which convergers

>>16838278
that is analytically not computationally
if i showed you a sequence like 4, 4, 4, 4, 4,... and then told you the sequence converges to 17 eventually would you agree it converges to 17? A sequence i made myself so only i know the full sequence

>>16838210
1/9 = 0.111...
+
8/9 = 0.888...
=
9/9 = 0.999...

>>16835161 (OP)
i never understood why i can't start the decimals from highest to lowest to actually create an infinite list of all irrational numbers
0.000
0.100
0.200
...
0.900
0.010
0.110
0.210
...
0.990
0.001
...
and so on and so on
there, a complete list of every irrational number

>>16838438
Because anything that doesn't end in 000... can't have a numbered position in that list. Like 1/3 for example. You'd have to say it's in the ...333rd position but ...333 isn't a natural number.

>>16838210
0.9 (exact)

>>16838484
>9/10 = 8/9
lol

>>16835161 (OP)
The diagonal argument is trash for midwits.
[math]2^n > n[/math]
Simple as.