Thread 16837925

How do you get through without being filtered by trick questions?

My answer to this is 63. Would they let me in?

This must be a troll. The wording is too imprecise to be a real math question.

>>16837940
It's not to test your math, but your morality and how you think.

The question is do they want people that will entertain degenerate solutions that involve polygamy like OP or is that a deal breaker?

>>16837951
You don't even need to resort to polygamy. They all could have 7 children from previous marriages.

>>16837925 (OP)
>63
Show your work dumb bass

>>16837967
All 7 men are married to the same 7 women, they share. 14 adults.
Each women has a child by each man. 49 kids.
Wa la.

What's your solution smart guy?

>>16837925 (OP)
7 men
49 wives
343 children
399 people in total

>>16837965
How do you get an answer of 63 without polygamy?

>>16837975
350. I don't count women.

>>16837986
343 kids, not a single daughter? Get real anon.

What gender do the husbands and wives identify as?
Here is your 1 million dollar grant money

>>16837984
The normal way: each couple has 7 children (so 7x7=49) plus the 7 men + 7 women = 63

>>16838000
>343 kids, not a single daughter
Inshallah

>>16837925 (OP)
>People
7 people total.

>>16837925 (OP)
7 men + 7 wife = 14 people ...1*
>each man and each wife have 7 children
1 person --- 7 children
2 person --- 14 children
.
.
.
14 person --- 98 children ...2*
>total number of people?
1* + 2* = 112 people

>>16837925 (OP)
52

1 man has a bastard daughter. (2)
He marries his daughter and has 6 sons. (2+6 = 8)
His eldest son impregnates his mom once and gives the father a granddaughter. (8 + 1 = 9)
The eldest son then marries the granddaughter (his daughter) and has 5 daughters with her, the great granddaughters (9+6=15)
5 of the great granddaughters marry their uncles and each have 7 kids (15 + 5*7 =50)
The 1st granddaughter is a cheating slut and gets pregnant two more time bringing her tally up to 7, but no one knows who the father is, maybe the neighbor or family dog (50+2=52)

Wa la. 7 men, 7 wives, each has 7 kids.

How can we further optimize this to get the number down lower?

>>16837925 (OP)
51

1 man has a bastard daughter. (2)
He marries his daughter and has 6 sons. (2+6 = 8)
His eldest son impregnates his mom once and gives the father a granddaughter. (8 + 1 = 9)
The eldest son then marries the granddaughter (his daughter) and has 5 daughters with her, the great granddaughters (9+5=14)
5 of the great granddaughters marry their uncles and each have 7 kids (14 + 5*7 =49)
The 1st granddaughter is a cheating slut and gets pregnant two more time bringing her tally up to 7, but no one knows who the father is, maybe the neighbor or family dog (49+2=51)

Wa la. 7 men, 7 wives, each has 7 kids.

How can we further optimize this to get the number down lower?

>>16837925 (OP)
51

1 man has a bastard daughter. (2)
He marries his daughter and has 6 sons. (2+6 = 8)
His eldest son impregnates his mom once and gives the father a granddaughter. (8 + 1 = 9)
The eldest son then marries the granddaughter (his daughter) and has 6 daughters with her, the great granddaughters (9+6=15)
5 of the great granddaughters marry their uncles and each have 7 kids (15 + 5*7 =50)
The initial granddaughter is a cheating slut and gets pregnant one more time bringing her tally up to 7, but no one knows who the father is, maybe the neighbor or family dog (50+1=51)

Wa la. 7 men, 7 wives, each has 7 kids.

How can we further optimize this to get the number down lower?

>>16837925 (OP)
I read it as 7 men 7 wives. 7 x7 and 7x7 is 49.2 98. I read the answer as 98 total. If its each then each guy has 7 wives and you can figure it out from there.

>>16837925 (OP)
this is more an english test than maths. does it mean there are 7 men each with 7 wives? are there 7 men and 7 wives? does each man and each wife have 7 children or does each marriage have 7 children?

it's the same as this shit. there are multiple solutions since the question itself is flawed

>>16837925 (OP)
49*2+14=112

Answer is 112.

>>16838180
Alternatively 49*7+8*7=399

>>16837978
>>16838185
>each man and each wife has 7 children
Are you guys retarded? If the man gives each of his 7 wives 7 kids, he has more than 7 children.
>>16838180
>>16838040
>2 person --- 14 children
....

Maybe this isn't a trick question and is just meant as a very basic filter for dummies.

Easy question. That would be 8.256 billion.

>>16838102
Family circle!! Family circle!!

>>16837925 (OP)
7

>>16837925 (OP)
Seems like a language question, not a math question.

>>16837925 (OP)
5-6 kids in each family dies before age 5, so 14-30 total people.

>>16837925 (OP)
But it says right there that 90% were eliminated. So there are only 6.3 people.

>>16838191
7 men have 7 wives each, that's 49 wives + 7 men = 56 adults. Every adult has 7 children, as "Each man AND each wife have 7 children". 56x7=392

392 kids + the 56 adults = 448.

>>16838604
It doesn't say "each wife has 7 children and each man has 49 children"
You've given the men far more kids than the instructions say.

>>16838617
We don't even know who's kids they are. None of the wive's kids could even be the husbands. Alternatively they could all be, so then you wouldn't add 7 for him. Then you could say some are his. In that case you could even surmise that some of the other men are other men's kids.

However the wording implies... "Each man and each wife" have 7 kids. Each and each. Not each man and wife has 7 kids.

its 21 bozos

7. Women and children aren't people in polygnist societies.

Answer is either 21, 63, 112, or 448 people. Note: 399 is an invalid answer as the men would either have 0 or 49 kids each there, but they need 7.

>>16837925 (OP)
Thoroughly ambiguous and therefore a trash question.
>7 men have 7 wives
Does each man have seven wives? Are there seven men and seven women?
>each man and each wife have 7 children
So each individual man has seven children, and each individual wife has seven children? Are these the same children between them? Or is it that each man-wife couple has seven children?
>what's the toal number of people
Men, wives and children as posed earlier in the question, or total number of people in general, which is in the billions?
This is clearly not a math test but an English or maybe Law test.

>>16839724
51 is a valid solution too. See >>16838102

Of seven men, there are seven wives. The problem doesn't specify you must only be married once. Each couple gets married, and has a child. They get divorced and remarry, and have no children. Repeat until each man has been married to each woman at least once. Per marriage laws, each man and each wife is a parent to each of the seven children. The problem is now satisfied with 21 unique people.

>>16837925 (OP)
>7 men have seven wives.
Doesn't say each, or anything that would imply some sort of abnormality. Therefore it is safe to assume that it means each dude is married to 1 female.
>Each man and EACH wife have 7 children
The second each is weird. It should have said each man and wife have 7 children, if it wanted to stay simple.
Therefore we have to assume it means 7 children each.
So 7*7 + 7*7 + 7+7 = 112

>>16839724
No there are more valid answers if incest is involved.

>>16837925 (OP)
>WIVES
It implies marriage
All the polyamory cucks are retarded, polyamorous marriage is not legal in the USA

>>16837925 (OP)
Total number of people is 8.2 billion and the rest of the problem is a red herring.
Yall got filtered hard.

>>16839724
>399 is an invalid answer
448 is also invalid on the grounds of given the men too many kids.

Men is always 7
An upper bound for the number of wives is 49 (under the interpretation)ach man owns 7 wives)
an upper bound for number of children is 2401 (under the interpretation that every pairing of one man with any of the 49 wives owns 7 children )
so the upper bound is 2457
A lower bound for wives is 7 (under the interpretation that the collective group of 7 men owns 7 wives)
a lower bound on children is 7 (under the interpretation that each person co-owns 7 children)
so the lower bound is 21
You can arbitrarily create numbers between the upper and lower bound, for example to get to 22, 7 men and 6 wives own a group of 7 children, while the 7th wife owns 6 children from the group and 1 child of her own
so the answer is any integer between 21 and 2457

>>16837925 (OP)
343 is the only real answer.
/thread

>>16838308
(5 + 0*sqrt(41)) / 2

>>16841035
>polyamorous marriage is not legal in the USA
Did you just national assume?