Search Results
6/27/2025, 11:54:03 PM
>>713837341
You don't even need the method since it's a one-line operation. Nor do you need the modulo to find out if a value is even, since an odd value will always have a 1 as its least-significant bit. So just do a bitwise-and and compare to 1:
>if ( (var & 1) == 1 ) { // odd } else { // even }
You don't even need the method since it's a one-line operation. Nor do you need the modulo to find out if a value is even, since an odd value will always have a 1 as its least-significant bit. So just do a bitwise-and and compare to 1:
>if ( (var & 1) == 1 ) { // odd } else { // even }
6/15/2025, 11:31:18 PM
Page 1