>>16749363
>>16754016
i disagree. using this volume and h = L cos(t) and R = r + 2Lsin(t), I get

[math]V(\theta) = \frac{4}{3}\pi L^3 \cos\theta \sin^2 \theta + 2\pi rL^2\sin\theta\cos\theta + \pi r^2L\cos\theta[/math]